0=2y^2-y-15

Solution for 0=2y^2-y-15 equation:

0=2y^2-y-15

We move all terms to the left:

0-(2y^2-y-15)=0

We add all the numbers together, and all the variables

-(2y^2-y-15)=0

We get rid of parentheses

-2y^2+y+15=0

a = -2; b = 1; c = +15;
Δ = b2-4ac
Δ = 12-4·(-2)·15
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-11}{2*-2}=\frac{-12}{-4}
=+3
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+11}{2*-2}=\frac{10}{-4}
=-2+1/2
$